4t=-16t^2+30t

Solution for 4t=-16t^2+30t equation:

4t=-16t^2+30t

We move all terms to the left:

4t-(-16t^2+30t)=0

We get rid of parentheses

16t^2-30t+4t=0

We add all the numbers together, and all the variables

16t^2-26t=0

a = 16; b = -26; c = 0;
Δ = b2-4ac
Δ = -262-4·16·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-26}{2*16}=\frac{0}{32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+26}{2*16}=\frac{52}{32}
=1+5/8
$